16x-12=8x^2(1/2)

Solution for 16x-12=8x^2(1/2) equation:

16x-12=8x^2(1/2)

We move all terms to the left:

16x-12-(8x^2(1/2))=0

We add all the numbers together, and all the variables

16x-(8x^2(+1/2))-12=0

We multiply all the terms by the denominator


16x*2))-(8x^2(+1-12*2))=0

We add all the numbers together, and all the variables

16x*2))-(8x^2(-23))=0

We add all the numbers together, and all the variables

16x*2))-(8x^2(=0

Wy multiply elements

32x^2=0

a = 32; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·32·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{64}=0$